Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.3 Geometric Sequences; Geometric Series - 12.3 Assess Your Understanding - Page 824: 47

Answer

$8191.75$

Work Step by Step

We have to compute the sum of the geometric sequence: $\dfrac{1}{4}+\dfrac{2}{4}+\dfrac{2^2}{4}+...+\dfrac{2^{14}}{4}$ The elements of the geometric sequence are: $a_1=\dfrac{1}{4}$ $r=2$ $n=15$ The sum can be written as: $\sum_{n=0}^{14}\dfrac{1}{4}(2^n)$ Use a graphing utility to find the sum of the geometric sequence: $sum\left(seq\left(\dfrac{1}{4}(2^n),n,0,14\right)\right)=8191.75$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.