Answer
$0.00000004.$
Work Step by Step
We know that $a_n=a_1r^{n-1}.$
where $r$=common ration (we can get this by dividing any two consecutive terms) and $a_1$= the first term
Here $a_1=0.4$ and $r=\frac{a_2}{a_1}=\dfrac{0.04}{0.4}=0.1$
Hence, here we have
$a_n=0.4(0.1)^{n-1}.$
Therefore $a_{8}=0.4(0.4)^{8-1}\\=0.00000004.$