Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.3 Geometric Sequences; Geometric Series - 12.3 Assess Your Understanding - Page 824: 2

Answer

$\$9513.28.$

Work Step by Step

According to the Compound Interest Formula, where $P$ is the principal, the amount deposited, $r$ is the annual interest rate, $n$ is the number of times the interest is compounded annually, $t$ is the number of years, $A$ is the amount you get back after $t$ years: $A=P\cdot(1+\frac{r}{n})^{n\cdot t}.$ Here we have: $t=1\text{ years}$ $r=5\%=0.05$ $A=\$10000$ $n=12$ (since it is compounded monthly) Substitute these values into the formula above to obtain: Here $\$10000=P\cdot(1+\frac{0.05}{12})^{12\cdot 1}.$ Thus $P=\frac{10000}{(1+\frac{0.05}{12})^{12\cdot1 }}\approx\$9513.28.$
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