Answer
$1-2^n$
Work Step by Step
We are given the sum:
$-1-2-4-8-....-(2^{n-1})$
Consider the geometric sequence:
$a_1=-1$
$r=2$
The given sum represents the sum $S_n$ of the first $n$ terms. Determine this sum:
$S_n=a_1\dfrac{1-r^n}{1-r}=(-1)\cdot\dfrac{1-2^n}{1-2}=1-2^n$