Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.3 Geometric Sequences; Geometric Series - 12.3 Assess Your Understanding - Page 824: 4

Answer

$\dfrac{a}{1-r}$

Work Step by Step

If $|r|<1$, the sum of the geometric series $\sum_{k=1}^{\infty} ar^{k-1}$ is $\dfrac{a}{1-r}$ because for the geometric series $ar^{k-1}$ with first term $a_1=ar^0=a$ and ratio $r$ where $|r|<1$, the sum is $\sum_{k=1}^{\infty} a_1r^{k-1}=\dfrac{a_1}{1-r}$.
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