Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.3 Geometric Sequences; Geometric Series - 12.3 Assess Your Understanding - Page 824: 49

Answer

$\approx 1.9954$

Work Step by Step

We have to compute the sum of the geometric sequence: $\sum_{n=1}^{15} \left(\dfrac{2}{3}\right)^n$ The elements of the geometric sequence are: $a_1=\dfrac{2}{3}$ $r=\dfrac{2}{3}$ $n=15$ Use a graphing utility to find the sum of the geometric sequence: $sum\left(seq\left((2/3)^n,n,1,15\right)\right)=\dfrac{28632278}{14348907}\approx 1.9954$
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