Answer
$2(3^n-1)$
Work Step by Step
We are given the sum:
$\sum_{k=1}^n 4\cdot 3^{k-1}$
Consider the geometric sequence:
$a_1=4\cdot 3^{1-1}=4$
$r=3$
The given sum represents the sum $S_n$ of the first $n$ terms. Determine this sum:
$S_n=a_1\dfrac{1-r^n}{1-r}=4\cdot\dfrac{1-3^n}{1-3}$
$=2(3^n-1)$