Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.3 Geometric Sequences; Geometric Series - 12.3 Assess Your Understanding - Page 824: 19


$a_n=2\cdot 3^{n-1}$ and $a_{5}=162.$

Work Step by Step

We know that if $a_1$ is the first term and $r$ is the common ratio, then the nth term is: $a_n=a_1\cdot r^{n-1}.$ Hence here $a_n=2\cdot 3^{n-1}$ and $a_{5}=2\cdot 3^{5-1}=162.$
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