Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 12 - Sequences; Induction; the Binomial Theorem - 12.3 Geometric Sequences; Geometric Series - 12.3 Assess Your Understanding - Page 824: 39

Answer

$(-1)^n7(15)^{n-2}$ $7(15)^{n-2}$

Work Step by Step

We are given the geometric sequence: $a_2=7$ $a_4=1575$ Determine the common ratio $r$: $\dfrac{a_4}{a_2}=\dfrac{1575}{7}$ $\dfrac{a_1r^3}{a_1r}=225$ $r^2=225$ $r=\pm\sqrt{225}$ $r=\pm 15$ Case 1: $r=-15$ Determine $a_1$: $a_2=a_1r$ $7=a_1\cdot (-15)$ $a_1=-\dfrac{7}{15}$ Determine $a_n$: $a_n=a_1r^{n-1}=-\dfrac{7}{15}(-15)^{n-1}=(-1)^n 7(15)^{n-2}$ Case 2: $r=15$ Determine $a_1$: $a_2=a_1r$ $7=a_1\cdot 15$ $a_1=\dfrac{7}{15}$ Determine $a_n$: $a_n=a_1r^{n-1}=\dfrac{7}{15}(15)^{n-1}=7(15)^{n-2}$
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