Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.4 The Definition Of Area As A Limit; Sigma Notation - Exercises Set 4.4 - Page 298: 11

Answer

$$5050$$

Work Step by Step

Given $$\sum_{k=1}^{100}k$$ Since $$\sum_{k=1}^{n}k=\frac{n(n+1)}{2}$$ Then \begin{align*} \sum_{k=1}^{100}k&=\frac{100(101)}{2}\\ &=50(101)\\ &=5050 \end{align*}
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