Answer
\begin{align}
\sum_{k=1}^{50} (2k-1) = 1 +3+5+... + 97+99
\end{align}
Work Step by Step
We can represent the odd integers as 2k-1. Thus, the sum of the odd integers from 1 to 99 can be represented in sigma notation as:
\begin{align}
\sum_{k=1}^{50} (2k-1) = 1 +3+5+... + 97+99
\end{align}