Calculus, 10th Edition (Anton)

Published by Wiley
ISBN 10: 0-47064-772-8
ISBN 13: 978-0-47064-772-1

Chapter 4 - Integration - 4.4 The Definition Of Area As A Limit; Sigma Notation - Exercises Set 4.4 - Page 298: 16

Answer

\[ -420 \]

Work Step by Step

Remember that: \[ \sum_{k=1}^{n} k^{3}=\left[\frac{(1+n)n}{2}\right]^{2} \] and \[ \sum_{k=1}^{n} k=\frac{(1+n)n}{2} \] We find: \[ \sum_{k=1}^{6} k-k^{3}=\sum_{k=1}^{6} k-\sum_{k=1}^{6} k^{3}=\left[\frac{(1+6)6}{2}\right]-\left[\frac{(1+6)6}{2}\right]^{2}=-420 \]
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