Answer
\[
-420
\]
Work Step by Step
Remember that:
\[
\sum_{k=1}^{n} k^{3}=\left[\frac{(1+n)n}{2}\right]^{2}
\]
and
\[
\sum_{k=1}^{n} k=\frac{(1+n)n}{2}
\]
We find:
\[
\sum_{k=1}^{6} k-k^{3}=\sum_{k=1}^{6} k-\sum_{k=1}^{6} k^{3}=\left[\frac{(1+6)6}{2}\right]-\left[\frac{(1+6)6}{2}\right]^{2}=-420
\]