Answer
\[
\frac{3+3 n}{2}
\]
Work Step by Step
Remember that:
\[
\sum_{k=1}^{n} k=\frac{(1+n)n}{2}
\]
We find:
\[
\sum_{k=1}^{n} \frac{3 k}{n}=\frac{3}{n} \sum_{k=1}^{n} k=\frac{3}{n} \cdot \frac{(1+n)n}{2}=\frac{3+3 n}{2}
\]
Calculus, 10th Edition (Anton)
by Anton, Howard
Published by
Wiley
ISBN 10:
0-47064-772-8
ISBN 13:
978-0-47064-772-1
Chapter 4 - Integration - 4.4 The Definition Of Area As A Limit; Sigma Notation - Exercises Set 4.4 - Page 298: 17
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