Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Review Exercises - Page 497: 50

Answer

$x=52$

Work Step by Step

LCD$=(3x+4)(2x-8)$, thus multiplying both sides by the LCD: $(3x+4)(2x-8)\frac{5}{3x+4}=(3x+4)(2x-8)\frac{3}{2x-8}\\5(2x-8)=3(3x+4)\\10x-40=9x+12\\x-40=12\\x=52$
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