Answer
$ \frac{3x+8}{3x+10}$.
Work Step by Step
The given expression is
$=\frac{3-\frac{1}{x+3}}{3+\frac{1}{x+3}}$
Multiply and divide the fraction by $(x+3)$.
$=\frac{(x+3)}{(x+3)}\cdot \frac{3-\frac{1}{x+3}}{3+\frac{1}{x+3}}$
Use the distributive property.
$= \frac{(x+3)\cdot 3-(x+3)\cdot \frac{1}{x+3}}{(x+3)\cdot 3+(x+3)\cdot \frac{1}{x+3}}$
Simplify.
$= \frac{3x+9-1}{3x+9+1}$
$= \frac{3x+8}{3x+10}$.
