Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Review Exercises - Page 497: 44

Answer

$f(2)=3$.

Work Step by Step

The given equation is $f(x)=2x^3-5x^2+4x-1$. If the given equation is divided by $x-2$ the remainder is $f(2)$. Use synthetic division to divide. Use synthetic division $\begin{matrix} 2) &2&-5&4&-1 \\ & &4&-2&4 \\ & --&--&--& --\\ & 2&-1&2&3 ​\end{matrix}$ The remainder $3$, is the value of $f(2)$. Check: $\Rightarrow f(2)=2(2)^3-5(2)^2+4(2)-1$. Simplify. $\Rightarrow f(2)=16-20+8-1$. $\Rightarrow f(2)=24-21$. $\Rightarrow f(2)=3$.
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