Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Review Exercises - Page 497: 41

Answer

$4x^2-7x+5-\frac{4}{x+1}$.

Work Step by Step

The given expression is $=(4x^3-3x^2-2x+1)\div(x+1)$ The value of $c$ is $-1$ Use synthetic division $\begin{matrix} -1) &4&-3&-2&1 \\ & &-4&7&-5 \\ & --&--&--& --\\ & 4&-7&5&-4 ​\end{matrix}$ The quotient is $4x^2-7x+5$ and the remainder is $-4$. The answer is $\Rightarrow Quotient + \frac{Remainder}{Divisor}$ $\Rightarrow 4x^2-7x+5-\frac{4}{x+1}$.
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