Answer
$ 3x-7+\frac{26}{2x+3}$.
Work Step by Step
The given expression is
$(6x^2-5x+5)\div(2x+3)$
$\begin{matrix}
& 3x & -7 & & \leftarrow &Quotient\\
&-- &-- &--& \\
2x+3) &6x^2&-5x&+5 & \\
& 6x^2 & +9x & & \leftarrow &3x(2x+3) \\
& -- & -- & & \leftarrow &subtract \\
& 0 & -14x & +5 & \\
& & -14x & -21 & \leftarrow & -7(2x+3) \\
& & -- & -- & \leftarrow & subtract \\
& & 0&26 &\leftarrow & Remainder
\end{matrix}$
The answer is
$\Rightarrow Quotient + \frac{Remainder}{Divisor}$
$\Rightarrow 3x-7+\frac{26}{2x+3}$.
