Answer
$x^3-4x^2+16x-64+\frac{272}{x+4}$.
Work Step by Step
The given expression is
$(x^4+16)\div(x+4)$
Rewrite as $(x^4+0x^3+0x^2+0x+16)\div(x+4)$
The value of $c$ is $-4$.
Use synthetic division
$\begin{matrix}
-4) &1&0&0&0&16 \\
& &-4&16&-64&256 \\
& --&--&--& --&--\\
& 1&-4&16&-64&272
\end{matrix}$
The quotient is $x^3-4x^2+16x-64$ and the remainder is $272$.
The answer is
$\Rightarrow Quotient + \frac{Remainder}{Divisor}$
$\Rightarrow x^3-4x^2+16x-64+\frac{272}{x+4}$.
