Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Review Exercises - Page 497: 29

Answer

$\frac{3}{8}$.

Work Step by Step

The given expression is $=\frac{\frac{3}{x}-3}{\frac{8}{x}-8}$ Divide and multiply the fraction by $x$. $=\frac{x}{x}\cdot \frac{\frac{3}{x}-3}{\frac{8}{x}-8}$ Use the distributive property. $= \frac{x\cdot\frac{3}{x}-x\cdot3}{x\cdot\frac{8}{x}-x\cdot8}$ Simplify. $= \frac{3-3x}{8-8x}$ Factor the fraction as shown below. $= \frac{3(1-x)}{8(1-x)}$ Cancel common terms. $= \frac{3}{8}$.
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