Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 134: 77


$x=-3\pm i$

Work Step by Step

$x^{2}+6x+10=0$ Use the quadratic formula to solve this equation. The formula is $x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. For this equation, $a=1$, $b=6$ and $c=10$. Substitute the known values into the formula and simplify: $x=\dfrac{-6\pm\sqrt{6^{2}-4(1)(10)}}{2(1)}=\dfrac{-6\pm\sqrt{36-40}}{2}=...$ $...=\dfrac{-6\pm\sqrt{-4}}{2}=\dfrac{-6\pm2i}{2}=-3\pm i$
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