Answer
$x=-3\pm i$
Work Step by Step
$x^{2}+6x+10=0$
Use the quadratic formula to solve this equation. The formula is $x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}$. For this equation, $a=1$, $b=6$ and $c=10$.
Substitute the known values into the formula and simplify:
$x=\dfrac{-6\pm\sqrt{6^{2}-4(1)(10)}}{2(1)}=\dfrac{-6\pm\sqrt{36-40}}{2}=...$
$...=\dfrac{-6\pm\sqrt{-4}}{2}=\dfrac{-6\pm2i}{2}=-3\pm i$
