Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 134: 11



Work Step by Step

$Evaluate$ $the$ $expression:$ $$2^{\frac{1}{2}}8^{\frac{1}{2}}$$ $$2^{\frac{1}{2}}8^{\frac{1}{2}} = (2\times8)^{\frac{1}{2}}$$ $$16^{\frac{1}{2}} = \sqrt {16}$$ $$=4$$
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