Answer
$x=\pm4i$
Work Step by Step
$x^{2}+16=0$
Take $16$ to the right side:
$x^{2}=-16$
Take the square root of both sides:
$\sqrt{x^{2}}=\sqrt{-16}$
$x=\pm4i$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Review - Exercises - Page 134: 75
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