Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 134: 75



Work Step by Step

$x^{2}+16=0$ Take $16$ to the right side: $x^{2}=-16$ Take the square root of both sides: $\sqrt{x^{2}}=\sqrt{-16}$ $x=\pm4i$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.