## Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole

# Chapter 1 - Review - Exercises - Page 134: 28

#### Answer

$3xy^{2}(3x^{2}+4xy^{2}-y^{3})$

#### Work Step by Step

$12x^{2}y^{4}-3xy^{5}+9x^{3}y^{2}$ Take out common factor $3xy^{2}$: $12x^{2}y^{4}-3xy^{5}+9x^{3}y^{2}=3xy^{2}(4xy^{2}-y^{3}+3x^{2})=...$ Rearrange: $...=3xy^{2}(3x^{2}+4xy^{2}-y^{3})$

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