Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 134: 31



Work Step by Step

$Factor$ $the$ $expression$ $completely:$ $x^6-1$ $x^6-1 = (x+1)(x-1)(x^4-1)$ $(x+1)(x-1)(x^4-1)$ = $(x+1)(x-1)(x^2-1)(x^2+1)$ $(x+1)(x-1)(x^2-1)(x^2+1)$ = $(x+1)(x^2+x+1)(x-1)(x^2-x+1)$
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