Answer
$(x+1)(x^2+x+1)(x-1)(x^2-x+1)$
Work Step by Step
$Factor$ $the$ $expression$ $completely:$
$x^6-1$
$x^6-1 = (x+1)(x-1)(x^4-1)$
$(x+1)(x-1)(x^4-1)$ = $(x+1)(x-1)(x^2-1)(x^2+1)$
$(x+1)(x-1)(x^2-1)(x^2+1)$ = $(x+1)(x^2+x+1)(x-1)(x^2-x+1)$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 1 - Review - Exercises - Page 134: 31
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