Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 134: 51


($\sqrt 11^{}$) / 11

Work Step by Step

To rationalize this denominator, we will have to get rid of the square root on the bottom, and the only way to do this is to multiply the denominator by $\sqrt 11^{}$. 1. Multiply both numerator and denominator by $\sqrt 11^{}$ 2. This gives you $\sqrt 11^{}$ in the numerator and $\sqrt 121^{}$ in the denominator, which simplifies to 11
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