Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 134: 13

Answer

$$\frac{1}{6}$$

Work Step by Step

$Evaluate$ $the$ $expression:$ $$216^{-\frac{1}{3}}$$ $$216^{-\frac{1}{3}} = \frac{1}{216^{\frac{1}{3}}}$$ $$\frac{1}{216^{\frac{1}{3}}} = \frac{1}{\sqrt[3] {216}}$$ $$=\frac{1}{6}$$
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