Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 134: 33


$x^{-1/2}(x+1)(5x-3)$ or $\dfrac{(x+1)(5x-3)}{x^{1/2}}$ or $\dfrac{(x+1)(5x-3)}{\sqrt{x}}$

Work Step by Step

$-3x^{-1/2}+2x^{1/2}+5x^{3/2}$ Take out common factor $x^{-1/2}$: $-3x^{-1/2}+2x^{1/2}+5x^{3/2}=x^{-1/2}(-3+2x+5x^{2})=...$ Rearrange the expression inside the parentheses: $...=x^{-1/2}(5x^{2}+2x-3)=...$ Factor the parentheses: $...=x^{-1/2}(x+1)(5x-3)$
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