Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 134: 58



Work Step by Step

$(x+2)^{2}=(x-4)^{2}$ Evaluate the powers on both sides: $x^{2}+4x+4=x^{2}-8x+16$ Since $x^{2}$ is repeated on both sides, it can be removed from the equation $4x+4=-8x+16$ Take $-8x$ to the left side and $4$ to the right side: $4x+8x=16-4$ Evaluate the operations on both sides: $12x=12$ Take $12$ to divide the right side: $x=\dfrac{12}{12}=1$ $x=1$
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