Answer
$a)$ $3+i$
$b)$ $8-i$
Work Step by Step
$a)$ $(2-3i)+(1+4i)$
Evaluate the sum:
$(2-3i)+(1+4i)=(2+1)+(-3+4)i=3+i$
$b)$ $(2+i)(3-2i)$
Evaluate the product:
$(2+i)(3-2i)=6-4i+3i-2i^{2}=...$
Substitute $i^{2}$ by $-1$ and simplify:
$...=6-4i+3i-2(-1)=6-i+2=8-i$