#### Answer

$(4x^{2}$ + 3)(x - 2)

#### Work Step by Step

Since this is a cubic polynomial, we will not be able to factor it normally like a second degree polynomial. For cubic polynomials, you need to group the function into 2 separate groups of like factors and factor them.
1. So the first group I decided to use was $4x^{2}$ and 8$x^{2}$ since they both have a 4 and $x^{2}$ in common.
2. Factoring the group mentioned above, you get $4x^{2}$(x - 2).
3. For the second group, I used the last two terms 3x and -6.
4. These two terms have a 3 in common between them both.
5. Factoring the 3x and -6 mentioned above, we get 3(x - 2).
6. Combing our factored forms we get from both groups we get $4x^{2}$(x - 2) + 3(x - 2).
7. Now you have a common factored terms, (x-2).
8. The other factored group is the terms that are left.
9. So our final factored form is $(4x^{2}$ + 3)(x - 2).