Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises: 52

Answer

($\sqrt 6$) / 2

Work Step by Step

1. We must multiply numerator and denominator by $\sqrt 6$ to get rid of radical in the denominator, thus rationalizing 2. Multiplying Numerator by $\sqrt 6$ to get 3$\sqrt 6$ 3. Multiplying Denominator by $\sqrt 6$ you get $\sqrt 36$ which simplifies to 6 4. Our answer is now 3$\sqrt 6$ / 6 which simplifies to ($\sqrt 6$) / 2
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