Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 134: 57


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Work Step by Step

$\dfrac{x+1}{x-1}=\dfrac{3x}{3x-6}$ Take $x-1$ to multiply the right side and $3x-6$ to multiply the left side: $(x+1)(3x-6)=3x(x-1)$ Evaluate the products on both sides: $3x^{2}-6x+3x-6=3x^{2}-3x$ Evaluate the operations on both sides: $3x^{2}-3x-6=3x^{2}-3x$ Take all terms to the left side: $3x^{2}-3x-6-3x^{2}+3x=0$ Simplify the left side: $-6\ne0$ This equation has no solution
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