## Precalculus: Mathematics for Calculus, 7th Edition

$\dfrac{\sqrt{242}}{\sqrt{2}}=11$
$\dfrac{\sqrt{242}}{\sqrt{2}}$ Rewrite this expression as the square root of a fraction: $\dfrac{\sqrt{242}}{\sqrt{2}}=\sqrt{\dfrac{242}{2}}=...$ Evaluate the division and after that, the square root: $...=\sqrt{121}=11$