Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Review - Exercises - Page 134: 30



Work Step by Step

$Factor$ $the$ $expression$ $completely:$ $2y^6-32y^2$ Factor out $2y^2$ $2y^2(y^4-16)$ Use the Difference of Squares Formula $2y^2(y^4-16) = 2y^2(y^2-4)(y^2+4)$ Use the Difference of Squares Formula for $y^2-4$ $2y^2(y^2-4)(y^2+4) = 2y^2(y+2)(y-2)(y^2+4)$
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