Answer
$2y^2(y+2)(y-2)(y^2+4)$
Work Step by Step
$Factor$ $the$ $expression$ $completely:$
$2y^6-32y^2$
Factor out $2y^2$
$2y^2(y^4-16)$
Use the Difference of Squares Formula
$2y^2(y^4-16) = 2y^2(y^2-4)(y^2+4)$
Use the Difference of Squares Formula for $y^2-4$
$2y^2(y^2-4)(y^2+4) = 2y^2(y+2)(y-2)(y^2+4)$
