Answer
Two complex solutions that are not real and conjugates of each other.
Work Step by Step
Subtract $2x$ from both sides.
$x^2+6-2x=2x-2x$
Simplify.
$x^2-2x+6=0$
The equation above has $a=1,b=-2$ and $c=6$.
The discriminant is
$b^2-4ac$
$=(-2)^2-4(1)(6)$
$=4-24$
$=-20$
Since $-20<0$, then the equation has two complex solutions that are not real and conjugates of each other.
