Answer
$-1$
Work Step by Step
Note that:
$i^{14}=(i^{2})^{7}$
Use $i^2=-1$.
$=(-1)^{7}$
Simplify.
$=-1$
Hence, the solution in the standard form is $-1$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Appendix A - Review - A.7 Complex Numbers; Quadratic Equations in the Complex Number System - A.7 Assess Your Understanding - Page A61: 36
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