Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.7 Complex Numbers; Quadratic Equations in the Complex Number System - A.7 Assess Your Understanding - Page A61: 49

Answer

$2i$

Work Step by Step

Factor the radicand so that one factor is a perfect square and another is $-1$ to obtain: $\sqrt{-4}=\sqrt{4(-1)}$ Use the rule $\sqrt{a\cdot b}=\sqrt{a} \cdot \sqrt{b}$ tp obtain: $=\sqrt{4}\cdot \sqrt{-1}$ Use $\sqrt{4}=2$ and $\sqrt{-1}=i$: $=2\cdot i$ $=2i$ Hence, the solution in the standard form is $2i$.
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