Answer
$\{-2,2\}$
Work Step by Step
Add $4$ to both sides.
$x^2-4+4=0+4$
Simplify.
$x^2=4$
Use square root property.
$x=\pm \sqrt{4}$
Use $\sqrt{4}=2$.
$x=\pm 2$
Hence, the solution set is $\{-2,2\}$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Appendix A - Review - A.7 Complex Numbers; Quadratic Equations in the Complex Number System - A.7 Assess Your Understanding - Page A61: 56
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