Answer
The solutions are two complex numbers that are not real and are conjugates of each other.
Work Step by Step
The given quadratic equation has $a=3,b=-3$ and $c=4$.
The discriminant is
$b^2-4ac$
$=(-3)^2-4(3)(4)$
$=9-48$
$=-39$
Since $-39<0$, the solutions are two complex numbers that are not real and are conjugates of each other.
