Answer
$0$
Work Step by Step
Write $i^7$ as $i^6 \cdot i$ to obtain:
$i^7(1+i^2)=i^6\cdot i(1+i^2)$
Write $i^6$ as $(i^2)^3$:
$=(i^2)^3\cdot i(1+i^2)$
Use $i^2=-1$.
$=(-1)^3\cdot i[1+(-1)]$
$=(-1)^3\cdot i(1-1)$
$=-1\cdot i(0)$
$=0$
Hence, the solution in the standard form is $0$.
