Answer
$-6$
Work Step by Step
Write $i^6$ as $\left(i^2\right)^3$ to obtain:
$i^{6}-5=(i^{2})^3-5$
Use $i^2=-1$.
$=(-1)^3-5$
$=-1-5$
$=-6$
Hence, the solution in standard form is $-6$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Appendix A - Review - A.7 Complex Numbers; Quadratic Equations in the Complex Number System - A.7 Assess Your Understanding - Page A61: 39
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