Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Appendix A - Review - A.7 Complex Numbers; Quadratic Equations in the Complex Number System - A.7 Assess Your Understanding - Page A61: 41

Answer

$-10i$

Work Step by Step

The given expression equivalent to: $6i^3-4i^{5}=6i^3-4i^{3}\cdot i^2$ Use $i^3=-i$ and $i^2=-1$. $=6(-i)-4(-i)\cdot (-1)$ $=-6i+4i\cdot (-1)$ $=-6i-4i$ $=-10i$ Hence, the solution in the standard form is $-10i$.
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