Answer
$-i$
Work Step by Step
Note that:
$\begin{align*}
i^{23}&=i^{22}\cdot i\\
&=i^{2(11)}\cdot i\\
&=(i^{2})^{11}\cdot i\\
\end{align*}$
Use $i^2=-1$.
$=(-1)^{11}\cdot i$
$=-1\cdot i$
$=-i$
Hence, the solution in the standard form is $-i$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Appendix A - Review - A.7 Complex Numbers; Quadratic Equations in the Complex Number System - A.7 Assess Your Understanding - Page A61: 35
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
