Answer
$\{-4,4\}$
Work Step by Step
Add $16$ to both sides.
$x^2-16+16=0+16$
Simplify.
$x^2=16$
Use square root property.
$x=\pm \sqrt{16}$
Use $\sqrt{16}=4$.
$x=\pm 4$
Hence, the solution set is $\{-4,4\}$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Appendix A - Review - A.7 Complex Numbers; Quadratic Equations in the Complex Number System - A.7 Assess Your Understanding - Page A61: 57
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
