Answer
$\{-5i,5i\}$
Work Step by Step
Subtract $25$ from both sides.
$x^2+25-25=0-25$
Simplify.
$x^2=-25$
Use square root property.
$x=\pm \sqrt{-25}$
$x=\pm \sqrt{25(-1)}$
$x=\pm \sqrt{25}\cdot \sqrt{-1}$
Use $\sqrt{16}=4$ and $\sqrt{-1}=i$.
$x=\pm 5i$
Hence, the solution set is $\{-5i,5i\}$.
