Appendix A - Review - A.7 Complex Numbers; Quadratic Equations in the Complex Number System - A.7 Assess Your Understanding - Page A61: 77

Two unequal real solutions.

Subtract $4$ from both sides. $2x^2+3x-4=4-4$ Simplify. $2x^2+3x-4=0$ The equation above has $a=2,b=3$ and $c=-4$. The discriminant is $b^2-4ac$ $=(3)^2-4(2)(-4)$ $=9+32$ $=41$ Since $41>0$, then the equation has two unequal real solutions.