Answer
The solutions has two unequal real number solutions.
Work Step by Step
The given quadratic equation has $a=2,b=-4$ and $c=1$.
The discriminant is
$b^2-4ac$
$=(-4)^2-4(2)(1)$
$=16-8$
$=8$
Since $8>0$, then the equation has two unequal real number solutions.
