Intermediate Algebra: Connecting Concepts through Application

Published by Brooks Cole
ISBN 10: 0-53449-636-9
ISBN 13: 978-0-53449-636-4

Chapter 8 - Radical Functions - 8.5 Complex Numbers - 8.5 Exercises - Page 663: 68

Answer

$\frac{107}{101}+\frac{41}{101} i$

Work Step by Step

Rewrite the given expression, and solve the latter. \begin{equation} \frac{-8-14 i}{-11-9 i} = \frac{8+14 i}{11+9 i}. \end{equation}Multiply both numerator and denominator by the conjugate of the denominator and simplify. \begin{equation} \begin{aligned} \frac{8+14 i}{11+9 i}&=\frac{8+14 i}{11+9 i}\cdot \frac{(11-9 i)}{(11-9 i)}\\ & =\frac{8(11-9 i)+14i(11-9 i)}{121+81}\\ &=\frac{88-72i+154i+126}{202}\\ &= \frac{214}{202}+\frac{82}{202} i \\ & = \frac{107}{101}+\frac{41}{101} i. \end{aligned} \end{equation}
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