Answer
$-60+32i$
Work Step by Step
$(2+8i)(2+8i)$
$=2(2+8i)+8i(2+8i)$
$=4+16i+16i+64i^{2}$
$=4+32i+64(-1)$
$=4+32i-64$
$=-60+32i$
Intermediate Algebra: Connecting Concepts through Application
by Clark, Mark; Anfinson, Cynthia
Published by
Brooks Cole
ISBN 10:
0-53449-636-9
ISBN 13:
978-0-53449-636-4
Chapter 8 - Radical Functions - 8.5 Complex Numbers - 8.5 Exercises - Page 663: 49
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